4(2-3x)=-[6x-(8-6x)]

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Solution for 4(2-3x)=-[6x-(8-6x)] equation:


Simplifying
4(2 + -3x) = -1[6x + -1(8 + -6x)]
(2 * 4 + -3x * 4) = -1[6x + -1(8 + -6x)]
(8 + -12x) = -1[6x + -1(8 + -6x)]
8 + -12x = -1[6x + (8 * -1 + -6x * -1)]
8 + -12x = -1[6x + (-8 + 6x)]

Reorder the terms:
8 + -12x = -1[-8 + 6x + 6x]

Combine like terms: 6x + 6x = 12x
8 + -12x = -1[-8 + 12x]
8 + -12x = [-8 * -1 + 12x * -1]
8 + -12x = [8 + -12x]

Add '-8' to each side of the equation.
8 + -8 + -12x = 8 + -8 + -12x

Combine like terms: 8 + -8 = 0
0 + -12x = 8 + -8 + -12x
-12x = 8 + -8 + -12x

Combine like terms: 8 + -8 = 0
-12x = 0 + -12x
-12x = -12x

Add '12x' to each side of the equation.
-12x + 12x = -12x + 12x

Combine like terms: -12x + 12x = 0
0 = -12x + 12x

Combine like terms: -12x + 12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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